using Nonemm.Spotting.Telnet;

namespace Nonemm.Spotting.Tests;

public class LineAssemblerTests
{
    [Fact]
    public void CompleteLinesComeOutWithoutTheirEndings()
    {
        LineAssembler assembler = new();

        Assert.Equal(["one", "two"], assembler.Add("one\r\ntwo\r\n"));
        Assert.Equal("", assembler.Pending);
    }

    [Fact]
    public void ALineSplitOverTwoBlocksIsPutBackTogether()
    {
        LineAssembler assembler = new();

        Assert.Empty(assembler.Add("DX de W3"));
        Assert.Equal(["DX de W3LPL"], assembler.Add("LPL\r\n"));
    }

    /// The login prompt has no line ending, so it only ever shows up here.
    [Fact]
    public void TextWithNoLineEndingWaitsInPending()
    {
        LineAssembler assembler = new();

        Assert.Empty(assembler.Add("login: "));
        Assert.Equal("login: ", assembler.Pending);
    }

    /// N1MM splits on CR alone, so some nodes evidently leave the LF out.
    [Fact]
    public void ALineEndedWithACarriageReturnAloneIsStillALine()
    {
        LineAssembler assembler = new();

        Assert.Equal(["one", "two"], assembler.Add("one\rtwo\r"));
    }

    [Fact]
    public void CarriageReturnAndLineFeedTogetherAreOneEnding()
    {
        LineAssembler assembler = new();

        Assert.Equal(["one"], assembler.Add("one\r\n"));
        Assert.Equal("", assembler.Pending);
    }

    [Fact]
    public void AnEndingSplitAcrossTwoBlocksIsStillOneEnding()
    {
        LineAssembler assembler = new();

        Assert.Equal(["one"], assembler.Add("one\r"));
        Assert.Empty(assembler.Add("\n"));
    }
}